Here's how to make a quick estimate. Let's start by dividing the two numbers:
[math]\frac{70^{71}}{71^{70}} = 70\cdot\left(\frac{70}{71}\right)^{70}= 70\cdot\left(1-\frac{1}{71}\right)^{70}[/math]
Now, if you have a sufficient background, you should recognize that [math](1-1/(n+1))^n[/math] goes towards [math]1/e[/math] as [math]n[/math]goes towards infinity. For [math]n=70[/math] we will already be pretty close.
Hence, not only do we know that [math]70^{71}[/math] is the greater of our two numbers, we can also estimate that their ratio is roughly [math]70/e \approx 26[/math].